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Lösning 4.4:8

FörberedandeFysik

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Rad 4: Rad 4:
<math>230 = \sqrt{(115)^2 + (U_c)^2} \Rightarrow U_c = 199,2 V</math> <math>U_c = I\cdot 1/ \omega C</math><br\>
<math>230 = \sqrt{(115)^2 + (U_c)^2} \Rightarrow U_c = 199,2 V</math> <math>U_c = I\cdot 1/ \omega C</math><br\>
<math>C = 1,1 \cdot 10^{-4} F(110\mu F)</math><br\>
<math>C = 1,1 \cdot 10^{-4} F(110\mu F)</math><br\>
 +
[[Bild:losning_4_4_8.jpg]]
[[Bild:losning_4_4_8.jpg]]

Versionen från 26 januari 2010 kl. 09.59

P=800W U=115V P=UI800=115I
I=696A =314rads

230=(115)2+(Uc)2Uc=1992V  Uc=I1C
C=11104F(110F)


Bild:losning_4_4_8.jpg