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(New page: The normal force <math>R</math> is equal to the weight <math>mg</math> of the sledge. Thus <math>R=mg=117 \textrm{.}6\ \text{N}</math>. The maximum frictional force is <math>F=\mu R</ma...)
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The normal force \displaystyle R is equal to the weight \displaystyle mg of the sledge.
Thus \displaystyle R=mg=117 \textrm{.}6\ \text{N}.
The maximum frictional force is \displaystyle F=\mu R where the coefficient of friction \displaystyle \mu = 0 \textrm{.}3.
Thus the maximum frictional force is \displaystyle F=35 \textrm{.}28\text{ N}.
If \displaystyle P is greater than \displaystyle 35 \textrm{.}28\text{ N} then the sledge will accelerate.
