From Mechanics

The normal force \displaystyle R is equal to the weight \displaystyle mg of the sledge.

Thus \displaystyle R=mg=117 \textrm{.}6\ \text{N}.

The maximum frictional force is \displaystyle F=\mu R where the coefficient of friction \displaystyle \mu = 0 \textrm{.}3.

Thus the maximum frictional force is \displaystyle F=35 \textrm{.}28\text{ N}.

If \displaystyle P is greater than \displaystyle 35 \textrm{.}28\text{ N} then the sledge will accelerate.