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	<math>\begin{align}		<math>\begin{align}
-	& \uparrow :\ \text{Resultant}\ \text{Force}=T-300\times 9.81=300\times 0.1 \\	+	& \uparrow :\ \text{Resultant}\ \text{Force}=T-300\times 9 \textrm{.}81=300\times 0 \textrm{.}1 \\
	& \\		& \\
	& T=30+2943\approx 2970\ \text{N} \\		& T=30+2943\approx 2970\ \text{N} \\
	\end{align}</math>		\end{align}</math>

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Revision as of 09:56, 20 May 2010

Here \displaystyle T is the tension in the cable and \displaystyle a is the acceleration of the packet.

Applying Newton's second law

\displaystyle \begin{align} & \uparrow :\ \text{Resultant}\ \text{Force}=T-300\times 9 \textrm{.}81=300\times 0 \textrm{.}1 \\ & \\ & T=30+2943\approx 2970\ \text{N} \\ \end{align}