Solution 10.1a
From Mechanics
Here \displaystyle T is the tension in the cable and \displaystyle a is the acceleration of the packet.
Applying Newton's second law
\displaystyle \begin{align} & \uparrow :\ \text{Resultant}\ \text{Force}=T-300\times 9 \textrm{.}81= ma = 300\times 0 \textrm{.}1 \\ & \\ & T=30+2943\approx 2970\ \text{N} \\ \end{align}