Answer 8.5a

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(New page: <math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math> <math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math>)
Current revision (10:38, 14 April 2010) (edit) (undo)
 
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<math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math>
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<math>\mathbf{v}=(80+t\ )\mathbf{i}+(4t \ )\mathbf{j}</math>
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<math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math>
+
<math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{\ 2}} \right)\mathbf{i}+2{{t}^{\ 2}}\mathbf{j}</math>

Current revision

\displaystyle \mathbf{v}=(80+t\ )\mathbf{i}+(4t \ )\mathbf{j}

\displaystyle \mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{\ 2}} \right)\mathbf{i}+2{{t}^{\ 2}}\mathbf{j}