Answer 8.5a
From Mechanics
(Difference between revisions)
(New page: <math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math> <math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math>) |
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- | <math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math> | + | <math>\mathbf{v}=(80+t\ )\mathbf{i}+(4t \ )\mathbf{j}</math> |
- | <math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math> | + | <math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{\ 2}} \right)\mathbf{i}+2{{t}^{\ 2}}\mathbf{j}</math> |
Current revision
\displaystyle \mathbf{v}=(80+t\ )\mathbf{i}+(4t \ )\mathbf{j}
\displaystyle \mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{\ 2}} \right)\mathbf{i}+2{{t}^{\ 2}}\mathbf{j}