Solution 13.2
From Mechanics
(Difference between revisions)
(New page: {| width="100%" cellspacing="10px" align="center" |align="left"| Force | valign="top"|Moment (Nm) |- |8 N at <math>D</math> | valign="top"| <math>-8\times 2=16</math> |- |20 N at <math>...) |
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Line 4: | Line 4: | ||
|- | |- | ||
|8 N at <math>D</math> | |8 N at <math>D</math> | ||
- | | valign="top"| <math>-8\times 2=16</math> | + | | valign="top"| <math>-8\times 2=-16</math> |
|- | |- | ||
|20 N at <math>D</math> | |20 N at <math>D</math> | ||
Line 12: | Line 12: | ||
| valign="top"| <math>-18\times 5=-90</math> | | valign="top"| <math>-18\times 5=-90</math> | ||
|- | |- | ||
- | | | + | |16 N at <math>C</math> |
- | | valign="top"| <math> | + | | valign="top"| <math>16\times 2=32</math> |
|- | |- | ||
- | | | + | |24 N at <math>B</math> |
- | | valign="top"| <math> | + | | valign="top"| <math>24\times 0=0</math> |
|- | |- | ||
|4 N | |4 N |
Revision as of 11:06, 26 June 2010
Force | Moment (Nm) |
8 N at \displaystyle D | \displaystyle -8\times 2=-16 |
20 N at \displaystyle D | \displaystyle 20\times 0=0 |
18 N at \displaystyle C | \displaystyle -18\times 5=-90 |
16 N at \displaystyle C | \displaystyle 16\times 2=32 |
24 N at \displaystyle B | \displaystyle 24\times 0=0 |
4 N | \displaystyle 4\times 0\textrm{.}5=2 |
Total Moment | \displaystyle 0-9\textrm{.}6+0-3+6+2=-4\textrm{.}6\text{ Nm} |