Solution 13.2

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Force Perpendicular Moment (Nm)
distance (m)
8 N at \displaystyle D 2 \displaystyle -8\times 2=-16
20 N at \displaystyle D 0 \displaystyle 20\times 0=0
18 N at \displaystyle C 5 \displaystyle -18\times 5=-90
16 N at \displaystyle C 2 \displaystyle 16\times 2=32
24 N at \displaystyle B 0 \displaystyle 24\times 0=0
Total Moment \displaystyle -16+0-90+32+0=-74\text{ Nm}