Solution 10.1a

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Here <math>T</math> is the tension in the cable and <math>a</math> is the acceleration of the packet.
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Applying Newton's second law
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<math>\begin{align}
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& \uparrow :\ \text{Resultant}\ \text{Force}=T-300\times 9.81=300\times 0.1 \\
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& \\
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& T=30+2943\approx 2970\ \text{N} \\
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\end{align}</math>

Revision as of 09:03, 20 May 2010

Image:10.1.gif

Here \displaystyle T is the tension in the cable and \displaystyle a is the acceleration of the packet.

Applying Newton's second law

\displaystyle \begin{align} & \uparrow :\ \text{Resultant}\ \text{Force}=T-300\times 9.81=300\times 0.1 \\ & \\ & T=30+2943\approx 2970\ \text{N} \\ \end{align}

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