Solution 13.2

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(New page: {| width="100%" cellspacing="10px" align="center" |align="left"| Force | valign="top"|Moment (Nm) |- |8 N at <math>D</math> | valign="top"| <math>-8\times 2=16</math> |- |20 N at <math>...)
Current revision (10:42, 2 August 2010) (edit) (undo)
 
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{| width="100%" cellspacing="10px" align="center"
{| width="100%" cellspacing="10px" align="center"
|align="left"| Force
|align="left"| Force
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| valign="top"|Perpendicular
| valign="top"|Moment (Nm)
| valign="top"|Moment (Nm)
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|-
 +
|
 +
| valign="top"| distance (m)
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| valign="top"|
|-
|-
|8 N at <math>D</math>
|8 N at <math>D</math>
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| valign="top"| <math>-8\times 2=16</math>
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| valign="top"|2
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| valign="top"| <math>-8\times 2=-16</math>
|-
|-
|20 N at <math>D</math>
|20 N at <math>D</math>
 +
| valign="top"|0
|valign="top"| <math>20\times 0=0</math>
|valign="top"| <math>20\times 0=0</math>
|-
|-
|18 N at <math>C</math>
|18 N at <math>C</math>
 +
| valign="top"|5
| valign="top"| <math>-18\times 5=-90</math>
| valign="top"| <math>-18\times 5=-90</math>
|-
|-
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|6 N
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|16 N at <math>C</math>
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| valign="top"| <math>-6\times 0\textrm{.}5=-3</math>
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| valign="top"|2
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|-
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| valign="top"| <math>16\times 2=32</math>
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|5 N
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-
| valign="top"| <math>5\times 1\textrm{.}2=6</math>
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|-
|-
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|4 N
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|24 N at <math>B</math>
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| valign="top"| <math>4\times 0\textrm{.}5=2</math>
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| valign="top"|0
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| valign="top"| <math>24\times 0=0</math>
|-
|-
|Total Moment
|Total Moment
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| valign="top"| <math>0-9\textrm{.}6+0-3+6+2=-4\textrm{.}6\text{ Nm}</math>
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| valign="top"| <math>-16+0-90+32+0=-74\text{ Nm}</math>
|}
|}

Current revision

Force Perpendicular Moment (Nm)
distance (m)
8 N at \displaystyle D 2 \displaystyle -8\times 2=-16
20 N at \displaystyle D 0 \displaystyle 20\times 0=0
18 N at \displaystyle C 5 \displaystyle -18\times 5=-90
16 N at \displaystyle C 2 \displaystyle 16\times 2=32
24 N at \displaystyle B 0 \displaystyle 24\times 0=0
Total Moment \displaystyle -16+0-90+32+0=-74\text{ Nm}
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