Solution 6.5a

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  • (cur) (last) 15:43, 8 April 2010 Ian (Talk | contribs) (234 bytes) (New page: Using <math>s=ut+\frac{1}{2}a{{t}^{\ 2}}\ \</math> gives <math>s=0+\frac{1}{2}0\textrm{.}5\times {{10}^{2}}=25\ \text{m}</math> Using <math>v=u+at\ \</math> gives <math>v=0+0\textrm{.}...)
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