From Mechanics

Using \displaystyle s=ut+\frac{1}{2}a{{t}^{\ 2}}\ \ gives

\displaystyle s=0+\frac{1}{2}0\textrm{.}5\times {{10}^{2}}=25\ \text{m}

Using \displaystyle v=u+at\ \ gives

\displaystyle v=0+0\textrm{.}5\times 10=5\ \text{m}{{\text{s}}^{-1}}