Solution 16.7a
From Mechanics
Using
\displaystyle {{m}_{A}}{{\mathbf{v}}_{A}}+{{m}_{B}}{{\mathbf{v}}_{B}}={{m}_{A}}{{\mathbf{u}}_{A}}+{{m}_{B}}{{\mathbf{u}}_{B}}
and
\displaystyle {{\mathbf{u}}_{A}}={{\mathbf{u}}_{B}}
Assume the particles have mass \displaystyle m
\displaystyle \begin{align} & m(5\mathbf{i})+m(8\mathbf{j})=2m\mathbf{v} \\ & \mathbf{v}=2\textrm{.}5\mathbf{i}+4\mathbf{j} \\ & v=\sqrt{{{2\textrm{.}5}^{2}}+{{4}^{2}}}=4\textrm{.}72\text{ m}{{\text{s}}^{\text{-1}}} \\ \end{align}