Solution 15.9b

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\displaystyle \begin{align} & \tan \alpha =\frac{2}{4} \\ & \alpha =26\textrm{.}6{}^\circ \\ \end{align}

\displaystyle \text{Angle between Impulse and Initial Velocity}=180-26\textrm{.}6={{153\textrm{.}4}^{\circ }}