Solution 14.7b
From Mechanics
Using part a, we see from the figure that
\displaystyle F=S=\frac{98}{\tan \theta } and \displaystyle R=196
\displaystyle \begin{align}
& F\le \mu R \\
& \frac{98}{\tan \theta }\le 0\textrm{.}6\times 196 \\
& \tan \theta \ge \frac{98}{0\textrm{.}6\times 196} \\
& \theta \ge 39\textrm{.}8{}^\circ \\
\end{align}