Solution 14.6a
From Mechanics
The diagram shows the forces acting on the ladder.
Taking moments about the base of the ladder:
\displaystyle \begin{align} & 5\sin 70{}^\circ \times S=2\textrm{.}5\cos 70{}^\circ \times 245 \\ & S=\frac{2\textrm{.}5\cos 70{}^\circ \times 245}{5\sin 70{}^\circ }=44\textrm{.}59\text{ N} \\ \end{align}
Considering the horizontal forces \displaystyle F=S=44\textrm{.}59\text{ N}
Considering the vertical forces \displaystyle R=245\text{ N}