Solution 4.4b

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Image:teori4.gif

\displaystyle \tan \alpha =\frac{V}{H}

Here \displaystyle V=-10\ \text{N} and \displaystyle H=9\ \text{N}.

Thus

\displaystyle \tan \alpha =\frac{-10}{9}=-1\textrm{.}1 giving \displaystyle \alpha =-48{}^\circ