Solution 3.3

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Image:2.1.gif

First consider the lower mass.

If \displaystyle T={{T}_{1}} is the tension in the lower string then


\displaystyle mg=7\times 9\textrm{.}8=68\textrm{.}6\ \text{N}


giving \displaystyle {{T}_{1}}=68\textrm{.}6\ \text{N}


If \displaystyle T={{T}_{2}} is the tension in the upper string then the two masses are regarded as one particle with total mass 15 kg.

Thus in this case


\displaystyle mg=15\times 9\textrm{.}8=147\ \text{N}


giving \displaystyle {{T}_{2}}=147\ \text{N}