Solution to Test Paper 2

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Solutions
1 (a) \displaystyle \begin{align}

& 44.1=\frac{1}{2}\times 9.8{{t}^{2}} \\ & t=\sqrt{\frac{44.1}{4.9}}=3\text{ s} \\ \end{align}

OR

\displaystyle \begin{align} & s=\frac{1}{2}\times 9.8\times {{3}^{2}}=44.1 \\ & \text{AG} \\ & \therefore \text{Hits ground after 3 seconds} \\ \end{align}



M1

A1

A1


(M1)

(A1)

(A1)


(3 marks) M1: Use of constant acceleration

equation with \displaystyle v=0

A1: Correct equation

A1: Correct \displaystyle s


1 (b) 2 3 4
1 (c) 2 3 4
1 2 3 4
2 (a) 2 3 4
2 (b) 2 3 4
2 (c) 2 3 4
2 (d) 2 3 4
1 2 3 4
3 (a) 2 3 4
3 (b) 2 3 4
3 (c) 2 3 4
1 2 3 4
4 (a) 2 3 4
4 (b) 2 3 4
4 (c) 2 3 4
1 2 3 4
5 (a) 2 3 4
5 (b) 2 3 4
5 (c) 2 3 4


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