Solution 19.7a

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\displaystyle \mathbf{a}=\frac{\mathbf{F}}{4}=\frac{12t\mathbf{i}+(6-5t)\mathbf{j}}{4}=3t\mathbf{i}+\left( \frac{3}{2}-\frac{5t}{4} \right)\mathbf{j}