Solution 14.7a

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The diagram shows the forces acting on the ladder.

Image:14.7.gif

Taking moments about the base of the ladder:

\displaystyle \begin{align} & 5\sin \theta \times S=2\textrm{.}5\cos \theta \times 196 \\ & S=\frac{2\textrm{.}5\cos \theta \times 196}{5\sin \theta }=\frac{98}{\tan \theta }\text{ N} \\ \end{align}