From Mechanics

\displaystyle \begin{align} & \mathbf{F}=F\cos \alpha \mathbf{i}+F\sin \alpha \mathbf{j} \end{align}

\displaystyle F1=40\ \text{N} and \displaystyle \alpha 1=20{}^\circ this gives

\displaystyle \begin{align} & \mathbf{F}1=40\cos 20{}^\circ \mathbf{i}+40\sin 20{}^\circ \mathbf{j}=40\times 0.94\mathbf{i}+40\times 0.342\mathbf{j} \\ & =37.6\mathbf{i}+13.7\mathbf{j} \\ \end{align}

\displaystyle F2=50\ \text{N} and \displaystyle \alpha 2=-30{}^\circ this gives

\displaystyle \begin{align} & \mathbf{F}2=50\cos \left( -30 \right) {}^\circ \mathbf{i}+50\sin \left( -30 \right) {}^\circ \mathbf{j}=50\times 0.866\mathbf{i}-50\times 0.50\mathbf{j} \\ & =43.3\mathbf{i}+25\mathbf{j} \\ \end{align}