Part 1
What is a force?
Force and gravity
Other forces
Forces and vectors
Part 2
Forces and equilibrium
Kinematics
Position Vectors
Constant acceleration
Part 3
Newton’s first law
Newton’s second law
Newton’s third law
Mathematical modelling
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Practice Test Paper 1
Solution to Test Paper 1
Practice Test Paper 2
Solution to Test Paper 2
Practice Test Paper 3
Solution to Test Paper 3
Part 4
Moments
Equilibrium
Momentum and impulse
Conservation of momentum
Part 5
Conservation of energy
Variable acceleration I
Variable acceleration II
Circular Motion
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Solution 18.3a
From Mechanics
Revision as of 17:30, 6 October 2010 by
Ian
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v
=
dt
dh
=
3
t
25
−
3
t
2
250
When
t
=
1
0
v
=
25
3
1
0
−
250
3
10
2
=
1
.
2
−
1
.
2
=
0
10−2503102=1.2−1.2=0
