Solution 8.4a
From Mechanics
Here we have \displaystyle \mathbf{a}=0.2\mathbf{i}+0.3\mathbf{j},\ \ \displaystyle \mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \ and \displaystyle \ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}.
Using \displaystyle \mathbf{v}=\mathbf{u}+\mathbf{a}t\ \ at \displaystyle \ \ t=10 gives
\displaystyle \mathbf{v}=4\mathbf{i}– 8\mathbf{j}+(0.2\mathbf{i}+0.3\mathbf{j})\times 10\ \ or
\displaystyle \mathbf{v}=6\mathbf{i}– 5\mathbf{j}
Using \displaystyle \mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}