Solutions
1 (a)
| \displaystyle \begin{align}
& 44 \ \textrm{.}1=\frac{1}{2}\times 9 \ \ 8{{t}^{2}} \\
& t=\sqrt{\frac{44 \textrm{.}1}{4 \textrm{.}9}}=3\text{ s} \\
\end{align}
OR
\displaystyle \begin{align}
& s=\frac{1}{2}\times 9 \textrm{.}8\times {{3}^{2}}=44 \textrm{.}1 \\
& \text{AG} \\
& \therefore \text{Hits ground after 3 seconds} \\
\end{align}
| M1
A1
A1
(M1)
(A1)
(A1)
| (3 marks)
| M1: Use of constant acceleration
equation with \displaystyle v=0
A1: Correct equation
A1: Correct \displaystyle s
|
1 (b)
| \displaystyle \begin{align}
& {{v}^{2}}={{0}^{2}}+2\times 9 \textrm{.}8\times 44 \textrm{.}1 \\
& v=\sqrt{864 \textrm{.}36}=29 \ \textrm{.}4\text{ m}{{\text{s}}^{-1}} \\
\end{align}
OR
\displaystyle \begin{align}
& v=0+9 \textrm{.}8\times 3 \\
& v=29 \textrm{.}4 \text{ m}{{\text{s}}^{-1}} \\
\end{align}
| M1
A1
A1
| (3 marks)
| M1: Use of constant acceleration equation with \displaystyle v=0
A1: Correct equation.
A1: Correct \displaystyle v.
|
1 (c)
| Air resistance would slow the ball down.
| B1
| (1 mark)
| B1: Sensible statement about air resistance.
|
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|
| (7 marks)
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2 (a)
|
| B1
| (1 mark)
| B1: Correct horizontal forces.
Ignore any vertical forces.
|
2 (b)
| \displaystyle P = 900 \text{N}
| B1
| (1 mark)
| B1: Correct value for \displaystyle P.
|
2 (c)
| \displaystyle \begin{align}
& P-900=2000\times 1\textrm{.}2 \\
& P=2400+900=3300 \text{N} \\
\end{align}
| M1
A1
A1
| (1 mark)
| M1: Three term equation of motion
A1: Correct equation
A1: Correct \displaystyle P.
|
2 (d)
| \displaystyle \begin{align}
& 800-900=2000a \\
& a=\frac{-100}{2000}=-0\textrm{.}05 \text{ m}{{\text{s}}^{-2}} \\
\end{align}
Car is slowing down
| M1
A1
A1
A1
| (4 marks)
| M1: Three term equation of motion
A1: Correct equation
A1: Correct \displaystyle a
A1: Correct statement
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| (9 marks)
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3 (a)
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| 5
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3 (b)
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3 (c)
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1
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4 (a)
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4 (b)
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4 (c)
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1
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5 (a)
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5 (b)
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5 (c)
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