Solution 8.9a
From Mechanics
Here we use \displaystyle \mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}} with
\displaystyle {{\mathbf{r}}_{0}}=1\textrm{.}5\mathbf{i} \text{ m}
\displaystyle \mathbf{u}=15\mathbf{i}+18\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}
\displaystyle \mathbf{a}=-10\mathbf{j}
\displaystyle t=3\text{ s}