Solution 6.10a
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(New page: Using <math>s=ut+\frac{1}{2}a{{t}^{\ 2}}</math> gives <math>s=0+\frac{1}{2}\times 2\times {{4}^{2}}=16\ \text{m}</math>)
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Using \displaystyle s=ut+\frac{1}{2}a{{t}^{\ 2}} gives
\displaystyle s=0+\frac{1}{2}\times 2\times {{4}^{2}}=16\ \text{m}
