Solution 6.5b
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(New page: Using <math>v=u+at\ \</math> gives <math>v=5+0\textrm{.}2\times 5=6\text{ m}{{\text{s}}^{-1}}</math> The distance travelled during this stage using <math>s=ut+\frac{1}{2}a{{t}^{\ 2}}\ \<...)
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Using \displaystyle v=u+at\ \ gives
\displaystyle v=5+0\textrm{.}2\times 5=6\text{ m}{{\text{s}}^{-1}}
The distance travelled during this stage using \displaystyle s=ut+\frac{1}{2}a{{t}^{\ 2}}\ \ is
\displaystyle s1=5\times 5+\frac{1}{2}0\textrm{.}2\times {{5}^{2}}=27\textrm{.}5\ \text{m}
Together with the first stage the total distance travelled is
\displaystyle 25+27\textrm{.}5=52\textrm{.}5\ \text{m}
