Solution 5.5b

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In the vertical direction the forces on the tank must be in equilibrium.
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<math>\uparrow \ -mg+N+5000\cos {{65}^{\circ }}=0</math>
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or
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<math>\begin{align}
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& N=mg-5000\cos {{65}^{\circ }}=500\times 9.8-5000\times 0.423 \\
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& =4900-2113=2787\ \text{N} \\
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\end{align}</math>

Revision as of 16:38, 4 April 2010

Image:5.5.gif

In the vertical direction the forces on the tank must be in equilibrium.

\displaystyle \uparrow \ -mg+N+5000\cos {{65}^{\circ }}=0

or

\displaystyle \begin{align} & N=mg-5000\cos {{65}^{\circ }}=500\times 9.8-5000\times 0.423 \\ & =4900-2113=2787\ \text{N} \\ \end{align}

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