Solution 5.2b
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(New page: Resolving horisontally to the right <math>\begin{align} & {{T}_{2}}-{{T}_{1}}\cos {{40}^{\circ }}=0 \\ & \\ & {{T}_{2}}={{T}_{1}}\cos {{40}^{\circ }}=762\times 0\textrm{.}766=584\ \te...)
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Resolving horisontally to the right
\displaystyle \begin{align}
& {{T}_{2}}-{{T}_{1}}\cos {{40}^{\circ }}=0 \\
& \\
& {{T}_{2}}={{T}_{1}}\cos {{40}^{\circ }}=762\times 0\textrm{.}766=584\ \text{N} \\
\end{align}
