Solution 5.2a
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(New page: Resolving vertically <math>\begin{align} & {{T}_{1}}\cos {{50}^{\circ }}-mg=0 \\ & \\ & {{T}_{1}}=\frac{mg}{\cos {{50}^{\circ }}}=\frac{490}{0\textrm{.}643}=762\ \text{N} \\ \end{ali...)
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Revision as of 15:54, 2 April 2010
Resolving vertically
\displaystyle \begin{align}
& {{T}_{1}}\cos {{50}^{\circ }}-mg=0 \\
& \\
& {{T}_{1}}=\frac{mg}{\cos {{50}^{\circ }}}=\frac{490}{0\textrm{.}643}=762\ \text{N} \\
\end{align}
