Solution 5.1d

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(New page: Here <math>F\le \mu N</math> <math>\mu</math> is the coefficient of friction. <math>\begin{align} & 67\textrm{.}0<\mu 184 \\ & \\ & \mu >\frac{67\textrm{.}0}{184} \\ & \\ & \mu >0\...)
Current revision (15:33, 2 April 2010) (edit) (undo)
 
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Here <math>F\le \mu N</math>
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Here <math>F\le \mu R</math>
<math>\mu</math>
<math>\mu</math>

Current revision

Here \displaystyle F\le \mu R

\displaystyle \mu is the coefficient of friction.

\displaystyle \begin{align} & 67\textrm{.}0<\mu 184 \\ & \\ & \mu >\frac{67\textrm{.}0}{184} \\ & \\ & \mu >0\textrm{.}364 \\ \end{align}