Solution 4.8b
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Ian (Talk | contribs)
(New page: Image:4.8b.gif <math>\tan \alpha =\frac{12}{9}=1\textrm{.}33</math> giving <math>\alpha =53\textrm{.}1{}^\circ</math>)
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\displaystyle \tan \alpha =\frac{12}{9}=1\textrm{.}33
giving
\displaystyle \alpha =53\textrm{.}1{}^\circ
