Solution 4.6b
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(New page: <math>\begin{align} & \mathbf{F}1=37\textrm{.}6\mathbf{i}+13\textrm{.}7\mathbf{j}\ \text{N}\\ \end{align}</math> <math>\begin{align} & \mathbf{F}2=43\textrm{.}3\mathbf{i}+25\mathbf{j} \...)
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Revision as of 15:27, 23 March 2010
\displaystyle \begin{align} & \mathbf{F}1=37\textrm{.}6\mathbf{i}+13\textrm{.}7\mathbf{j}\ \text{N}\\ \end{align}
\displaystyle \begin{align}
& \mathbf{F}2=43\textrm{.}3\mathbf{i}+25\mathbf{j} \ \text{N}\\
\end{align}
