Solution 4.5a
From Mechanics
(Difference between revisions)
Line 9: | Line 9: | ||
Here | Here | ||
- | <math>V= | + | <math>V=3\ \text{N}</math> and |
- | <math>H= | + | <math>H=4\ \text{N}</math>. |
Substituting the given values | Substituting the given values | ||
- | |||
<math>\begin{align} | <math>\begin{align} | ||
- | + | {{F}^{2}}={{4}^{2}}+{{3}^{2}}=25 \\ | |
- | + | ||
- | + | ||
\end{align}</math> | \end{align}</math> | ||
+ | giving | ||
+ | |||
+ | <math>\begin{align} | ||
+ | F=5\ \text{N} \\ | ||
+ | \end{align}</math> | ||
Also | Also |
Current revision
Using \displaystyle {{F}^{2}}={{H}^{2}}+{{V}^{2}}
and
\displaystyle \tan \alpha =\frac{V}{H}
Here
\displaystyle V=3\ \text{N} and \displaystyle H=4\ \text{N}.
Substituting the given values
\displaystyle \begin{align} {{F}^{2}}={{4}^{2}}+{{3}^{2}}=25 \\ \end{align}
giving
\displaystyle \begin{align} F=5\ \text{N} \\ \end{align}
Also
\displaystyle \tan \alpha =\frac{3}{4}=0\textrm{.}75
giving
\displaystyle \alpha =36\textrm{.}9{}^\circ