Solution 4.5a
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(New page: Image:teori4.gif Using <math>{{F}^{2}}={{H}^{2}}+{{V}^{2}}</math> Substituting the given values <math>\begin{align} & {{F}^{2}}={{4}^{2}}+{ {3}^{2}} =25 \\ & F=5 \text{ N} \\ \end...)
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Revision as of 09:58, 23 March 2010
Using \displaystyle {{F}^{2}}={{H}^{2}}+{{V}^{2}}
Substituting the given values
\displaystyle \begin{align} & {{F}^{2}}={{4}^{2}}+{ {3}^{2}} =25 \\ & F=5 \text{ N} \\ \end{align}
\displaystyle \tan \alpha =\frac{V}{H}
Here \displaystyle V=3\ \text{N} and \displaystyle H=4\ \text{N}.
Thus
\displaystyle \tan \alpha =\frac{3}{4}=0\textrm{.}75 giving \displaystyle \alpha =36\textrm{.}9{}^\circ
