Solution 4.4b
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(New page: Image:teori4.gif <math>\tan \alpha =\frac{V}{H}</math> Here <math>V=-10\ \text{N}</math> and <math>H=9\ \text{N}</math>. Thus <math>\tan \alpha =\frac{-10}{9}=-1\textrm{.}1</mat...)
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\displaystyle \tan \alpha =\frac{V}{H}
Here \displaystyle V=-10\ \text{N} and \displaystyle H=9\ \text{N}.
Thus
\displaystyle \tan \alpha =\frac{-10}{9}=-1\textrm{.}1 giving \displaystyle \alpha =-48{}^\circ
