Solution 4.3b
From Mechanics
(Difference between revisions)
Ian (Talk | contribs)
(New page: Image:teori4.gif <math>\tan \alpha =\frac{V}{H}</math> Here <math>V=8\ \text{N}</math> and <math>H=6\ \text{N}</math>. Thus <math>\tan \alpha =\frac{8}{6}=1\textrm{.}33</math> g...)
Next diff →
Current revision
\displaystyle \tan \alpha =\frac{V}{H}
Here \displaystyle V=8\ \text{N} and \displaystyle H=6\ \text{N}.
Thus
\displaystyle \tan \alpha =\frac{8}{6}=1\textrm{.}33 giving \displaystyle \alpha =53{}^\circ
