Solution 3.3
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Revision as of 09:59, 17 March 2010
First consider the lower mass.
If \displaystyle T=T1 is the tension in the lower string then
\displaystyle mg=7\times 9\textrm{.}8=68\textrm{.}6\ \text{N}
giving
\displaystyle T1=68\textrm{.}6\ \text{N}
If \displaystyle T=T2 is the tension in the upper string then the two masses are regarded as one particle with total mass 15 kg.
Thus in this case
\displaystyle mg=15\times 9\textrm{.}8=147\ \text{N}
giving
\displaystyle T2=147\ \text{N}