Solution 17.4b
From Mechanics
(Difference between revisions)
(New page: As the brick has no speed at the start <math>\text {KE = KE gained}</math>. Using Energy lost due to friction = Work done against friction we get, <math>\begin{align} & \text{PE lost - ...) |
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<math>\begin{align} | <math>\begin{align} | ||
- | & KE=\text{2}\times \text{9}\text{.8}\times \text{3}.2-1\text{0}\times \text{3}\text{.2}=\text{30}\text{.72 J} \\ | + | & KE=\text{2}\times \text{9}\text{.8}\times \text{3}\textrm{.}2-1\text{0}\times \text{3}\text{.2}=\text{30}\text{.72 J} \\ |
& \\ | & \\ | ||
& \frac{\text{1}}{\text{2}}\times 2{{v}^{2}}=30\textrm{.}72 \\ | & \frac{\text{1}}{\text{2}}\times 2{{v}^{2}}=30\textrm{.}72 \\ | ||
& v=5\textrm{.}54\text{ m}{{\text{s}}^{\text{-1}}} | & v=5\textrm{.}54\text{ m}{{\text{s}}^{\text{-1}}} | ||
\end{align}</math> | \end{align}</math> |
Current revision
As the brick has no speed at the start
\displaystyle \text {KE = KE gained}.
Using Energy lost due to friction = Work done against friction we get,
\displaystyle \begin{align} & \text{PE lost - KE gained = Work done against friction} \\ & \\ & \text{which}\ \text{gives} \\ & \\ & \text{KE = KE gained = PE lost - Work done against friction} \\ \end{align}
\displaystyle \begin{align} & KE=\text{2}\times \text{9}\text{.8}\times \text{3}\textrm{.}2-1\text{0}\times \text{3}\text{.2}=\text{30}\text{.72 J} \\ & \\ & \frac{\text{1}}{\text{2}}\times 2{{v}^{2}}=30\textrm{.}72 \\ & v=5\textrm{.}54\text{ m}{{\text{s}}^{\text{-1}}} \end{align}