Solution 13.3
From Mechanics
(Difference between revisions)
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Take moments about the pivoted end of the level, <math>O</math>. | Take moments about the pivoted end of the level, <math>O</math>. | ||
- | <math>1.5\sin {{60}^{\circ }}\times 80=1.5\times 0.866\times 80=103.9\ \text{N}</math> | + | <math>1 \textrm{.}5\sin {{60}^{\circ }}\times 80=1 \textrm{.}5\times 0 \textrm{.}866\times 80=103 \textrm{.}9\ \text{N}</math> |
Current revision
Take moments about the pivoted end of the level, \displaystyle O.
\displaystyle 1 \textrm{.}5\sin {{60}^{\circ }}\times 80=1 \textrm{.}5\times 0 \textrm{.}866\times 80=103 \textrm{.}9\ \text{N}