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Solution 9.5

From Mechanics

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Current revision (09:56, 6 March 2011) (edit) (undo)
 
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[[Image:9.5.gif]]
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[[Image:9.5a.gif]]
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In the figure <math>R1</math> is the air resistance.
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In the figure <math>F1</math> is the air resistance.
Resolving up the plane
Resolving up the plane

Current revision

Image:9.5a.gif

In the figure F1 is the air resistance.

Resolving up the plane

F1+F−mgsin20=0F1=mgsin20−F=609.810.342−F=201.3 N−F

Resolving perpendicular to the plane upwards

R−mgcos20=0R=mgcos20=609.810.94=553 N

Using the friction equation gives

F=R=0.05553=27.65 N

Substituting in the above equation for R1 gives

F1=201.3−27.65173 N

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