Solution to Test Paper 1
From Mechanics
(Difference between revisions)
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| - | <th> | + | <th>Question</th> |
| - | <th> | + | <th>Solution</th> |
| - | <th> | + | <th>Mark</th> |
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<tr> | <tr> | ||
| - | <td>1</td> | + | <td>1 (a) |
| - | <td> | + | |
| - | < | + | </td> |
| + | <td><math>\begin{align} | ||
| + | & {{0}^{2}}={{7}^{2}}+2(-9.8)s \\ | ||
| + | & s=\frac{49}{19.6}=2.5 \\ | ||
| + | & \text{Max Height }=\text{ 5}+\text{2}\text{.5}=\text{7}\text{.5 m} \\ | ||
| + | \end{align}</math></td> | ||
<td>3</td> | <td>3</td> | ||
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</tr> | </tr> | ||
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<td>2</td> | <td>2</td> | ||
<td>4</td> | <td>4</td> | ||
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<td>6</td> | <td>6</td> | ||
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Revision as of 19:15, 13 January 2011
| Question | Solution | Mark |
|---|---|---|
| 1 (a) | \displaystyle \begin{align}
& {{0}^{2}}={{7}^{2}}+2(-9.8)s \\ & s=\frac{49}{19.6}=2.5 \\ & \text{Max Height }=\text{ 5}+\text{2}\text{.5}=\text{7}\text{.5 m} \\ \end{align} |
3 |
| 2 | 2 | 4 |
| 3 | 3 | 6 |
