Solution 19.4b
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(New page: Using the result from part a) for the acceleration, <math>\begin{align} & v=\int{a}dt \\ & \\ & =\int{\left( \frac{2t}{5} \right)}dt \\ & \\ & =\frac{{{t}^{2}}}{5}+c \\ & \\ & t=...)
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Using the result from part a) for the acceleration,
\displaystyle \begin{align} & v=\int{a}dt \\ & \\ & =\int{\left( \frac{2t}{5} \right)}dt \\ & \\ & =\frac{{{t}^{2}}}{5}+c \\ & \\ & t=0,\ v=8\ \Rightarrow \ c=8 \\ & \\ & v=\frac{{{t}^{2}}}{5}+8 \end{align}
