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Solution 19.3b

From Mechanics

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Ian (Talk | contribs)
(New page: <math>\begin{align} & v=\int{a}dt \\ & \\ & =\int{\left( 8-\frac{4t}{5} \right)}dt \\ & \\ & =8t-\frac{2{{t}^{2}}}{5}+c \\ & \\ & t=0,\ v=0\ \Rightarrow \ c=0 \\ & \\ & v=8t-\f...)
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v=adt=8−54tdt=8t−52t2+ct=0 v=0  c=0v=8t−52t2v(10)=810−52102=40 ms-1

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