Solution 19.2a
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(New page: <math>\begin{align} & v=\int{a}dt=\frac{{{t}^{2}}}{50}+c \\ & \\ & t=0, \ \ v=2\ \Rightarrow \ c=2 \\ & \\ & v=\frac{{{t}^{2}}}{50}+2 \\ \end{align}</math>)
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\displaystyle \begin{align} & v=\int{a}dt=\frac{{{t}^{2}}}{50}+c \\ & \\ & t=0, \ \ v=2\ \Rightarrow \ c=2 \\ & \\ & v=\frac{{{t}^{2}}}{50}+2 \\ \end{align}
