Solution 19.1a
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(New page: <math>\begin{align} & v=\int{a}dt=t-\frac{{{t}^{2}}}{30}+c \\ & t=0,\ \ v=0\Rightarrow c=0 \\ & v=t-\frac{{{t}^{2}}}{30} \\ \end{align}</math>)
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\displaystyle \begin{align} & v=\int{a}dt=t-\frac{{{t}^{2}}}{30}+c \\ & t=0,\ \ v=0\Rightarrow c=0 \\ & v=t-\frac{{{t}^{2}}}{30} \\ \end{align}
