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Solution 18.7b

From Mechanics

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Ian (Talk | contribs)
(New page: <math>\begin{align} & \mathbf{v}=\frac{d\mathbf{r}}{dt}=40\mathbf{i}+(6t+20)\mathbf{j} \\ & \mathbf{v}(10)=40\mathbf{i}+(6\times 10+20)\mathbf{j}=40\mathbf{i}+80\mathbf{j} \\ & v(10)=\sq...)
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v=dtdr=40i+(6t+20)jv(10)=40i+(610+20)j=40i+80jv(10)=402+802=89.4 ms-1

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