From Mechanics

Revision as of 19:47, 7 October 2010 (edit) Ian (Talk | contribs) (New page: <math>\begin{align} & \mathbf{a}=\frac{d\mathbf{v}}{dt}=-4\mathbf{i}-10\mathbf{j} \\ & \mathbf{F}=5(-4\mathbf{i}-10\mathbf{j})=-20\mathbf{i}-50\mathbf{j} \\ & F=\sqrt{{{20}^{2}}+{{50}^{2...) ← Previous diff		Current revision (18:05, 8 October 2010) (edit) (undo) Ian (Talk | contribs)
Line 4:		Line 4:
	& F=\sqrt{{{20}^{2}}+{{50}^{2}}}=53\textrm{.}9\text{ N} \\		& F=\sqrt{{{20}^{2}}+{{50}^{2}}}=53\textrm{.}9\text{ N} \\
	\end{align}</math>		\end{align}</math>
		+
		+	This is independent of <math>t</math>.

---

Current revision

\displaystyle \begin{align} & \mathbf{a}=\frac{d\mathbf{v}}{dt}=-4\mathbf{i}-10\mathbf{j} \\ & \mathbf{F}=5(-4\mathbf{i}-10\mathbf{j})=-20\mathbf{i}-50\mathbf{j} \\ & F=\sqrt{{{20}^{2}}+{{50}^{2}}}=53\textrm{.}9\text{ N} \\ \end{align}

This is independent of \displaystyle t.