Solution 18.3a
From Mechanics
(Difference between revisions)
(New page: <math>v=\frac{dh}{dt}=\frac{3t}{25}-\frac{3{{t}^{2}}}{250}</math> When <math>t=\text{1}0</math> <math>v=\frac{3\times 10}{25}-\frac{3\times {{10}^{2}}}{250}=1 \textrm{.}2-1 \textrm{.}2...) |
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- | <math>v=\frac{ | + | <math>v=\frac{ds}{dt}=\frac{3t}{25}-\frac{3{{t}^{2}}}{250}</math> |
When | When |
Current revision
\displaystyle v=\frac{ds}{dt}=\frac{3t}{25}-\frac{3{{t}^{2}}}{250}
When \displaystyle t=\text{1}0
\displaystyle v=\frac{3\times 10}{25}-\frac{3\times {{10}^{2}}}{250}=1 \textrm{.}2-1 \textrm{.}2=0